Algebra • Step-by-Step

Solve x² + 6x + 9 = 0 with Steps

Solve x² + 6x + 9 = 0 step by step. Recognize (x + 3)² = 0 with discriminant Δ = 0 giving single root x = -3.

Problem Statement
x2+6x+9=0x^2 + 6x + 9 = 0
Final Result
x=−3x = -3

Formula Required: Perfect Square Trinomial

b² - 4ac = 36 - 36 = 0, meaning there is one repeated root.

(x+3)2=0  ⟹  x=−3(x + 3)^2 = 0 \implies x = -3

Step-by-Step Solution

6 Steps
1

Write the equation in standard quadratic form $ax^2 + bx + c = 0$.

x2+6x+9=0x^2 + 6x + 9 = 0
2

Find two numbers that multiply to $c = 9$ and add up to $b = 6$.

(3)×(3)=9,(3)+(3)=6(3) \times (3) = 9, \quad (3) + (3) = 6
3

Write the quadratic expression in factored form (perfect square trinomial).

(x+3)2=0(x + 3)^2 = 0
4

Set the factor equal to zero and solve for $x$.

x+3=0  ⟹  x=−3x + 3 = 0 \implies x = -3
5

Verify the solution by substituting back into the original equation.

Check x=−3:  (−3)2+6(−3)+9=9−18+9=0  ✓\text{Check } x = -3: \; (-3)^2 + 6(-3) + 9 = 9 - 18 + 9 = 0 \;\checkmark
6

Structural Insight (Vieta's Formulas): Notice how the sum and product of the roots directly confirm the original coefficients.

Sum of roots: x1+x2=−ba=−6,Product: x1⋅x2=ca=9\text{Sum of roots: } x_1 + x_2 = -\frac{b}{a} = -6, \quad \text{Product: } x_1 \cdot x_2 = \frac{c}{a} = 9

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Common Questions About Solve x² + 6x + 9 = 0

What is the root of x² + 6x + 9 = 0?

x = -3 (repeated root with multiplicity 2).

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