Calculus • Step-by-Step

Derivative of 3x² + 5x - 4 with Steps

Differentiate the polynomial 3x² + 5x - 4 term by term using power, linear, and constant rules to find 6x + 5.

Problem Statement
ddx[3x2+5x−4]\frac{d}{dx}[3x^2 + 5x - 4]
Final Result
f′(x)=6⋅x+5f'(x) = 6 \cdot x+5

Formula Required: Sum & Constant Multiple Rule

Differentiate each term independently and sum the results.

ddx[ax2+bx+c]=2ax+b\frac{d}{dx}[a x^2 + b x + c] = 2ax + b

Step-by-Step Solution

6 Steps
1

Set up the differentiation problem with respect to variable $x$.

ddx[3⋅x2+5⋅x−4]\frac{d}{dx} \left[ 3 \cdot x^{2}+5 \cdot x-4 \right]
2

Apply the Sum & Difference Rule: differentiate each term separately.

ddx[3⋅x2+5⋅x−4]=ddx[3⋅x2]+ddx[5⋅x]−ddx[−4]\frac{d}{dx} \left[ 3 \cdot x^{2}+5 \cdot x-4 \right] = \frac{d}{dx}\left[ 3 \cdot x^{2} \right] + \frac{d}{dx}\left[ 5 \cdot x \right] - \frac{d}{dx}\left[ -4 \right]
3

Differentiate $3 \cdot x^{2}$ using the Power Rule.

ddx[3⋅x2]=6⋅x\frac{d}{dx}\left[ 3 \cdot x^{2} \right] = 6 \cdot x
4

The derivative of linear term $5 \cdot x$ is its coefficient.

ddx[5⋅x]=5\frac{d}{dx}\left[ 5 \cdot x \right] = 5
5

The derivative of constant $4$ is $0$.

ddx[4]=0\frac{d}{dx}\left[ 4 \right] = 0
6

Combine all term derivatives and simplify algebraic terms.

ddx[3⋅x2+5⋅x−4]=6⋅x+5\frac{d}{dx}\left[ 3 \cdot x^{2}+5 \cdot x-4 \right] = 6 \cdot x+5

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Common Questions About Derivative of 3x² + 5x - 4

How do you differentiate a polynomial term-by-term?

Apply the power rule to each term: d/dx[3x²] = 6x, d/dx[5x] = 5, and d/dx[-4] = 0. Adding them gives 6x + 5.

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