Calculus • Step-by-Step

Derivative of csc(x) with Steps

Differentiate csc(x) step by step using the quotient rule or reciprocal identity 1/sin(x) to prove that d/dx[csc(x)] = -csc(x)cot(x) with full steps.

Problem Statement
ddx[csc⁡(x)]\frac{d}{dx}[\csc(x)]
Final Result
f′(x)=−cos(x)sin(x)2f'(x) = -\frac{\mathrm{cos}\left(x\right)}{\mathrm{sin}\left(x\right)^{2}}

Formula Required: Cosecant Derivative Rule

Differentiating (sin x)^(-1) yields -(sin x)^(-2) · cos x = -cos x / sin² x = -csc x cot x.

ddx[csc⁡(x)]=−csc⁡(x)cot⁡(x)\frac{d}{dx}[\csc(x)] = -\csc(x)\cot(x)

Step-by-Step Solution

2 Steps
1

Set up the differentiation problem with respect to variable $x$.

ddx[csc(x)]\frac{d}{dx} \left[ \mathrm{csc}\left(x\right) \right]
2

Apply the Power Rule to compute the derivative.

ddx[csc(x)]=−cos(x)sin(x)2\frac{d}{dx} \left[ \mathrm{csc}\left(x\right) \right] = -\frac{\mathrm{cos}\left(x\right)}{\mathrm{sin}\left(x\right)^{2}}

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Common Questions About Derivative of csc(x)

What is the derivative of csc(x)?

The derivative of csc(x) is -csc(x)cot(x).

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