Calculus • Step-by-Step

Derivative of tan(x) with Steps

Step-by-step differentiation of tan(x). Proved using the quotient rule on sin(x)/cos(x) to yield sec²(x).

Problem Statement
ddx[tan⁡(x)]\frac{d}{dx}[\tan(x)]
Final Result
f′(x)=sec(x)2f'(x) = \mathrm{sec}\left(x\right)^{2}

Formula Required: Quotient Rule & Tangent Derivative

Expressing tan(x) as sin(x)/cos(x) and applying quotient rule yields [cos²(x) + sin²(x)]/cos²(x) = 1/cos²(x) = sec²(x).

ddx[tan⁡(x)]=sec⁡2(x)\frac{d}{dx}[\tan(x)] = \sec^2(x)

Step-by-Step Solution

2 Steps
1

Set up the differentiation problem with respect to variable $x$.

ddx[tan(x)]\frac{d}{dx} \left[ \mathrm{tan}\left(x\right) \right]
2

Apply the Tangent Derivative to compute the derivative.

ddx[tan(x)]=sec(x)2\frac{d}{dx} \left[ \mathrm{tan}\left(x\right) \right] = \mathrm{sec}\left(x\right)^{2}

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Common Questions About Derivative of tan(x)

How do you derive d/dx[tan(x)] using the quotient rule?

Write tan(x) as sin(x)/cos(x). By quotient rule: (cos·cos - sin·(-sin))/cos² = (cos² + sin²)/cos² = 1/cos² = sec²(x).

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