Calculus • Step-by-Step

Integral of (5x⁴ - 2x³ + 7) dx with Steps

Integrate the polynomial 5x⁴ - 2x³ + 7 step by step. Apply the reverse power rule to each term to find the antiderivative x⁵ - (1/2)x⁴ + 7x + C.

Problem Statement
∫(5x4−2x3+7) dx\int (5x^4 - 2x^3 + 7) \, dx
Final Result
F(x)=x5−x42+7⋅x+CF(x) = x^{5}-\frac{x^{4}}{2}+7 \cdot x + C

Formula Required: Power Rule for Polynomials

5(x⁵/5) = x⁵, and -2(x⁴/4) = -(1/2)x⁴, and 7 integrates to 7x.

∫(5x4−2x3+7) dx=x5−12x4+7x+C\int (5x^4 - 2x^3 + 7) \, dx = x^5 - \frac{1}{2}x^4 + 7x + C

Step-by-Step Solution

6 Steps
1

Set up the indefinite integral with respect to variable $x$.

∫(5⋅x4−2⋅x3+7) dx\int \left( 5 \cdot x^{4}-2 \cdot x^{3}+7 \right) \, dx
2

Apply the Sum & Difference Rule: integrate each term separately.

∫(5⋅x4−2⋅x3+7) dx=∫5⋅x4 dx−∫2⋅x3 dx+∫7 dx\int \left( 5 \cdot x^{4}-2 \cdot x^{3}+7 \right) \, dx = \int 5 \cdot x^{4} \, dx - \int 2 \cdot x^{3} \, dx + \int 7 \, dx
3

Integrate term $5 \cdot x^{4}$ using the Power Rule for integration.

∫5⋅x4 dx=x5\int 5 \cdot x^{4} \, dx = x^{5}
4

Integrate term $2 \cdot x^{3}$ using the Power Rule for integration.

∫2⋅x3 dx=x42\int 2 \cdot x^{3} \, dx = \frac{x^{4}}{2}
5

Integrate constant $7$ to obtain $7 \cdot x$.

∫7 dx=7⋅x\int 7 \, dx = 7 \cdot x
6

Combine all term antiderivatives.

F(x)=x5−x42+7⋅xF(x) = x^{5}-\frac{x^{4}}{2}+7 \cdot x

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Common Questions About Integral of (5x⁴ - 2x³ + 7) dx

What is the integral of 5x⁴ - 2x³ + 7?

5(x⁵/5) - 2(x⁴/4) + 7x + C = x⁵ - (1/2)x⁴ + 7x + C.

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