Algebra • Step-by-Step

Solve x² - 25 = 0 with Steps

Solve x² - 25 = 0 step by step. Factors using difference of squares (x - 5)(x + 5) = 0 and square roots to find real roots x = 5 and x = -5.

Problem Statement
x2−25=0x^2 - 25 = 0
Final Result
x1=−5,x2=5x_1 = -5, \quad x_2 = 5

Formula Required: Difference of Squares

x² = 25 ⇒ x = ±5.

x2−25=(x−5)(x+5)=0x^2 - 25 = (x - 5)(x + 5) = 0

Step-by-Step Solution

6 Steps
1

Write the equation in standard quadratic form $ax^2 + bx + c = 0$.

x2−25=0x^2 - 25 = 0
2

Find two numbers that multiply to $c = -25$ and add up to $b = 0$.

(5)×(−5)=−25,(5)+(−5)=0(5) \times (-5) = -25, \quad (5) + (-5) = 0
3

Write the quadratic expression in factored form.

(x+5)(x−5)=0(x + 5)(x - 5) = 0
4

Set each factor equal to zero and solve for $x$.

x+5=0  ⟹  x1=−5orx−5=0  ⟹  x2=5x + 5 = 0 \implies x_1 = -5 \quad \text{or} \quad x - 5 = 0 \implies x_2 = 5
5

Verify each root by substituting back into the original equation.

Check x=−5:  (−5)2−25=25+0−25=0  ✓Check x=5:  (5)2−25=25+0−25=0  ✓\text{Check } x = -5: \; (-5)^2 - 25 = 25 + 0 - 25 = 0 \;\checkmark \\[6pt] \text{Check } x = 5: \; (5)^2 - 25 = 25 + 0 - 25 = 0 \;\checkmark
6

Structural Insight (Vieta's Formulas): Notice how the sum and product of the roots directly confirm the original coefficients.

Sum of roots: x1+x2=−ba=0,Product: x1⋅x2=ca=−25\text{Sum of roots: } x_1 + x_2 = -\frac{b}{a} = 0, \quad \text{Product: } x_1 \cdot x_2 = \frac{c}{a} = -25

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Common Questions About Solve x² - 25 = 0

What are the roots of x² - 25 = 0?

x = 5 and x = -5.

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