Algebra • Step-by-Step

Solve x² - 9 = 0 with Steps

Solve x² - 9 = 0 step by step using factoring (x - 3)(x + 3) = 0 and square roots x = ±3 with complete working.

Problem Statement
x2−9=0x^2 - 9 = 0
Final Result
x1=−3,x2=3x_1 = -3, \quad x_2 = 3

Formula Required: Difference of Two Squares

Take square roots of both sides or factor into (x - 3)(x + 3) = 0.

x2−a2=(x−a)(x+a)=0x^2 - a^2 = (x - a)(x + a) = 0

Step-by-Step Solution

6 Steps
1

Write the equation in standard quadratic form $ax^2 + bx + c = 0$.

x2−9=0x^2 - 9 = 0
2

Find two numbers that multiply to $c = -9$ and add up to $b = 0$.

(3)×(−3)=−9,(3)+(−3)=0(3) \times (-3) = -9, \quad (3) + (-3) = 0
3

Write the quadratic expression in factored form.

(x+3)(x−3)=0(x + 3)(x - 3) = 0
4

Set each factor equal to zero and solve for $x$.

x+3=0  ⟹  x1=−3orx−3=0  ⟹  x2=3x + 3 = 0 \implies x_1 = -3 \quad \text{or} \quad x - 3 = 0 \implies x_2 = 3
5

Verify each root by substituting back into the original equation.

Check x=−3:  (−3)2−9=9+0−9=0  ✓Check x=3:  (3)2−9=9+0−9=0  ✓\text{Check } x = -3: \; (-3)^2 - 9 = 9 + 0 - 9 = 0 \;\checkmark \\[6pt] \text{Check } x = 3: \; (3)^2 - 9 = 9 + 0 - 9 = 0 \;\checkmark
6

Structural Insight (Vieta's Formulas): Notice how the sum and product of the roots directly confirm the original coefficients.

Sum of roots: x1+x2=−ba=0,Product: x1⋅x2=ca=−9\text{Sum of roots: } x_1 + x_2 = -\frac{b}{a} = 0, \quad \text{Product: } x_1 \cdot x_2 = \frac{c}{a} = -9

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Common Questions About Solve x² - 9 = 0

What are the roots of x² - 9 = 0?

The roots are x = 3 and x = -3.

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