Algebra • Step-by-Step

Solve x² - 4 = 0 with Steps

Find the roots of x² - 4 = 0 step-by-step using difference of squares (x - 2)(x + 2) = 0 and square roots x = ±2.

Problem Statement
x2−4=0x^2 - 4 = 0
Final Result
x1=−2,x2=2x_1 = -2, \quad x_2 = 2

Formula Required: Difference of Squares Identity

Rewrite as x² - 2² = (x - 2)(x + 2) = 0.

a2−b2=(a−b)(a+b)=0a^2 - b^2 = (a - b)(a + b) = 0

Step-by-Step Solution

6 Steps
1

Write the equation in standard quadratic form $ax^2 + bx + c = 0$.

x2−4=0x^2 - 4 = 0
2

Find two numbers that multiply to $c = -4$ and add up to $b = 0$.

(2)×(−2)=−4,(2)+(−2)=0(2) \times (-2) = -4, \quad (2) + (-2) = 0
3

Write the quadratic expression in factored form.

(x+2)(x−2)=0(x + 2)(x - 2) = 0
4

Set each factor equal to zero and solve for $x$.

x+2=0  ⟹  x1=−2orx−2=0  ⟹  x2=2x + 2 = 0 \implies x_1 = -2 \quad \text{or} \quad x - 2 = 0 \implies x_2 = 2
5

Verify each root by substituting back into the original equation.

Check x=−2:  (−2)2−4=4+0−4=0  ✓Check x=2:  (2)2−4=4+0−4=0  ✓\text{Check } x = -2: \; (-2)^2 - 4 = 4 + 0 - 4 = 0 \;\checkmark \\[6pt] \text{Check } x = 2: \; (2)^2 - 4 = 4 + 0 - 4 = 0 \;\checkmark
6

Structural Insight (Vieta's Formulas): Notice how the sum and product of the roots directly confirm the original coefficients.

Sum of roots: x1+x2=−ba=0,Product: x1⋅x2=ca=−4\text{Sum of roots: } x_1 + x_2 = -\frac{b}{a} = 0, \quad \text{Product: } x_1 \cdot x_2 = \frac{c}{a} = -4

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Common Questions About Solve x² - 4 = 0

What are the solutions to x² - 4 = 0?

x = 2 and x = -2 (or x = ±2).

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