Calculus • Step-by-Step

Derivative of (2x + 1)³ with Steps

Step-by-step differentiation of (2x + 1)³ using the general power rule (chain rule) to get 6(2x + 1)².

Problem Statement
ddx[(2x+1)3]\frac{d}{dx}[(2x + 1)^3]
Final Result
f′(x)=6⋅(2⋅x+1)2f'(x) = 6 \cdot \left(2 \cdot x+1\right)^{2}

Formula Required: General Power Rule (Chain Rule)

Bring down the power, reduce the power by 1, and multiply by the derivative of the inside.

ddx[(g(x))n]=n(g(x))n−1⋅g′(x)\frac{d}{dx}[(g(x))^n] = n(g(x))^{n-1} \cdot g'(x)

Step-by-Step Solution

2 Steps
1

Set up the differentiation problem with respect to variable $x$.

ddx[(2⋅x+1)3]\frac{d}{dx} \left[ \left(2 \cdot x+1\right)^{3} \right]
2

Apply the Power Rule to compute the derivative.

ddx[(2⋅x+1)3]=6⋅(2⋅x+1)2\frac{d}{dx} \left[ \left(2 \cdot x+1\right)^{3} \right] = 6 \cdot \left(2 \cdot x+1\right)^{2}

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Common Questions About Derivative of (2x + 1)³

How do you differentiate (2x+1)³ without expanding?

Use the chain rule: 3(2x+1)² · d/dx[2x+1] = 3(2x+1)² · 2 = 6(2x+1)².

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