Calculus • Step-by-Step

Derivative of cos(2x) with Steps

Differentiate cos(2x) step by step using the Chain Rule. Identifies the inner function u = 2x and outer function cos(u) to yield -2sin(2x).

Problem Statement
ddx[cos⁡(2x)]\frac{d}{dx}[\cos(2x)]
Final Result
f′(x)=−2⋅sin(2⋅x)f'(x) = -2 \cdot \mathrm{sin}\left(2 \cdot x\right)

Formula Required: Chain Rule for Trigonometry

Differentiate cosine to -sine and multiply by the internal coefficient k.

ddx[cos⁡(kx)]=−ksin⁡(kx)\frac{d}{dx}[\cos(kx)] = -k \sin(kx)

Step-by-Step Solution

2 Steps
1

Set up the differentiation problem with respect to variable $x$.

ddx[cos(2⋅x)]\frac{d}{dx} \left[ \mathrm{cos}\left(2 \cdot x\right) \right]
2

Apply the Chain Rule to compute the derivative.

ddx[cos(2⋅x)]=−2⋅sin(2⋅x)\frac{d}{dx} \left[ \mathrm{cos}\left(2 \cdot x\right) \right] = -2 \cdot \mathrm{sin}\left(2 \cdot x\right)

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Common Questions About Derivative of cos(2x)

What is the derivative of cos(2x)?

The derivative of cos(2x) is -2sin(2x), found by chain rule: -sin(2x) · 2.

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