Calculus • Step-by-Step

Derivative of sin(3x) with Steps

Differentiate sin(3x) using the chain rule. Demonstrates multiplying the outer cosine derivative by the inner 3 to get 3cos(3x).

Problem Statement
ddx[sin⁡(3x)]\frac{d}{dx}[\sin(3x)]
Final Result
f′(x)=3⋅cos(3⋅x)f'(x) = 3 \cdot \mathrm{cos}\left(3 \cdot x\right)

Formula Required: Chain Rule for Trigonometric Functions

The derivative of sin(u) is cos(u) · du/dx.

ddx[sin⁡(kx)]=kcos⁡(kx)\frac{d}{dx}[\sin(kx)] = k \cos(kx)

Step-by-Step Solution

2 Steps
1

Set up the differentiation problem with respect to variable $x$.

ddx[sin(3⋅x)]\frac{d}{dx} \left[ \mathrm{sin}\left(3 \cdot x\right) \right]
2

Apply the Chain Rule to compute the derivative.

ddx[sin(3⋅x)]=3⋅cos(3⋅x)\frac{d}{dx} \left[ \mathrm{sin}\left(3 \cdot x\right) \right] = 3 \cdot \mathrm{cos}\left(3 \cdot x\right)

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Common Questions About Derivative of sin(3x)

What is the derivative of sin(3x)?

The derivative of sin(3x) is 3cos(3x).

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